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@ -5,6 +5,7 @@ int a[101];
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int sum[101]; // prefix sum
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int f[101][101];
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/*
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区间动态规划解题步骤:
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1.根据问题推测dp[i][j]的含义
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问题是:把第1堆到第n堆石子合成一堆,最小的得分
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