update

20240821/P1158/P1158.cpp

@@ -1,4 +1,7 @@
+#include <algorithm>
 #include <cctype>
+#include <climits>
+#include <cmath>
 #include <cstdio>
 #include <iostream>
 #include <ostream>
@@ -7,17 +10,41 @@ using namespace std;
 const int MAX_N = 1e5+5;
 
 struct Dir{
-    Dir(int x,int y):x(x),y(y){}
-    int x,y;
+    int x,y,dis1,dis2;
     friend ostream& operator<<(ostream &os,Dir d){
         os<<"Dir { x="<<d.x<<" ,y="<<d.y<<" } ";
         return os;
     }
-};
+}dirs[MAX_N];
 int readInt();
+int n;
+int ans=INT_MAX;
+int l1Max = INT_MIN;
+
+#define DIFF_SQU(a,b)(((a).x-(b).x)*((a).x-(b).x)+((a).y-(b).y)*((a).y-(b).y))
 
 int main(){
-    
+    Dir l1,l2;
+    l1.x=readInt(),l1.y=readInt(),l2.x=readInt(),l2.y=readInt();
+    n=readInt();
+    for(int i=1;i<=n;i++){
+        auto &di = dirs[i];
+        di.x=readInt(),di.y=readInt();
+        // l1Max=max(l1Max,(di.x-l1.x)*(di.x-l1.x)+(di.y-l1.y)*(di.y-l1.y));
+        di.dis1 = DIFF_SQU(di, l1);
+        di.dis2 = DIFF_SQU(di,l2);
+    }
+    sort(dirs+1,dirs+n+1,[](Dir a,Dir b)->bool{
+        return a.dis1<b.dis1;
+    });
+    int r2=0;
+    int ans=dirs[n].dis1;
+    for(int i=n-1;i>=1;i--){
+        if(dirs[i+1].dis2>r2)r2=dirs[i+1].dis2; //将距离拦截器一更远的那个纳入拦截器2的射程
+        ans=min(ans,dirs[i].dis1+r2);
+    }
+
+    cout<<ans<<endl;
 }
 
 int readInt(){