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Make is_template_base_of ignore cv qualification
`is_template_base_of<T>` fails when `T` is `const` (because its implementation relies on being able to convert a `T*` to a `Base<U>*`, which won't work when `T` is const). (This also agrees with std::is_base_of, which ignores cv qualification.)
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@ -378,9 +378,11 @@ inline internals &get_internals();
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#ifdef PYBIND11_CPP14
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using std::enable_if_t;
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using std::conditional_t;
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using std::remove_cv_t;
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#else
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template <bool B, typename T = void> using enable_if_t = typename std::enable_if<B, T>::type;
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template <bool B, typename T, typename F> using conditional_t = typename std::conditional<B, T, F>::type;
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template <typename T> using remove_cv_t = typename std::remove_cv<T>::type;
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#endif
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/// Index sequences
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@ -499,9 +501,9 @@ struct is_template_base_of_impl {
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/// `is_template_base_of<Base, T>` is true if `struct T : Base<U> {}` where U can be anything
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template <template<typename...> class Base, typename T>
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#if !defined(_MSC_VER)
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using is_template_base_of = decltype(is_template_base_of_impl<Base>::check((T*)nullptr));
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using is_template_base_of = decltype(is_template_base_of_impl<Base>::check((remove_cv_t<T>*)nullptr));
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#else // MSVC2015 has trouble with decltype in template aliases
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struct is_template_base_of : decltype(is_template_base_of_impl<Base>::check((T*)nullptr)) { };
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struct is_template_base_of : decltype(is_template_base_of_impl<Base>::check((remove_cv_t<T>*)nullptr)) { };
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#endif
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/// Check if T is std::shared_ptr<U> where U can be anything
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