Fix casting of time points with non-system-clock duration with VS (#1748)

* Fix casting of time points with non-system-clock duration on Windows

Add explicit `time_point_cast` to time point with duration of system
clock. Fixes Visual Studio compile error.

* Add test case for custom time points casting
This commit is contained in:
Alexander Gagarin 2019-06-13 12:17:10 +05:00 committed by Wenzel Jakob
parent ed39c50458
commit b3bf248eec
3 changed files with 15 additions and 1 deletions

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@ -128,7 +128,7 @@ public:
// Lazy initialise the PyDateTime import
if (!PyDateTimeAPI) { PyDateTime_IMPORT; }
std::time_t tt = system_clock::to_time_t(src);
std::time_t tt = system_clock::to_time_t(time_point_cast<system_clock::duration>(src));
// this function uses static memory so it's best to copy it out asap just in case
// otherwise other code that is using localtime may break this (not just python code)
std::tm localtime = *std::localtime(&tt);

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@ -14,6 +14,10 @@
TEST_SUBMODULE(chrono, m) {
using system_time = std::chrono::system_clock::time_point;
using steady_time = std::chrono::steady_clock::time_point;
using timespan = std::chrono::duration<int64_t, std::nano>;
using timestamp = std::chrono::time_point<std::chrono::system_clock, timespan>;
// test_chrono_system_clock
// Return the current time off the wall clock
m.def("test_chrono1", []() { return std::chrono::system_clock::now(); });
@ -44,4 +48,8 @@ TEST_SUBMODULE(chrono, m) {
// Float durations (issue #719)
m.def("test_chrono_float_diff", [](std::chrono::duration<float> a, std::chrono::duration<float> b) {
return a - b; });
m.def("test_nano_timepoint", [](timestamp start, timespan delta) -> timestamp {
return start + delta;
});
}

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@ -99,3 +99,9 @@ def test_floating_point_duration():
diff = m.test_chrono_float_diff(43.789012, 1.123456)
assert diff.seconds == 42
assert 665556 <= diff.microseconds <= 665557
def test_nano_timepoint():
time = datetime.datetime.now()
time1 = m.test_nano_timepoint(time, datetime.timedelta(seconds=60))
assert(time1 == time + datetime.timedelta(seconds=60))