fix: 修复P6003.cpp中的计算逻辑错误并调整P6003cal.cpp的打印顺序

修复P6003.cpp中check函数的计算逻辑，优化循环处理并提前返回结果
调整P6003cal.cpp中变量打印顺序以匹配实际计算流程

CMakeLists.txt

@@ -2,8 +2,8 @@ cmake_minimum_required(VERSION 3.15)
 
 set(CMAKE_EXPORT_COMPILE_COMMANDS ON)
 add_compile_options(-Wall)
-add_compile_options(-fsanitize=address,pointer-compare,pointer-subtract,undefined -fno-omit-frame-pointer)
-add_link_options(-fsanitize=address,pointer-compare,pointer-subtract,undefined -fno-omit-frame-pointer)
+# add_compile_options(-fsanitize=address,pointer-compare,pointer-subtract,undefined -fno-omit-frame-pointer)
+# add_link_options(-fsanitize=address,pointer-compare,pointer-subtract,undefined -fno-omit-frame-pointer)
 include_directories(${CMAKE_CURRENT_LIST_DIR}/include)
 
 set(CMAKE_CXX_STANDARD 26)

src/10/14/P4818.cpp

@@ -1,24 +1,39 @@
 #include <cstdint>
+#include <cstdio>
 #include <deque>
 #include <iostream>
 #include <istream>
 using ll = int64_t;
 
-const ll maxn = 1000+5;
+#define sl static inline
+
+const ll maxn = 1005;
 ll n, m;
-ll a[maxn][maxn];
-struct D{
-    ll x,y,d;
-    bool is2,ish;
-};
-std::deque<D> d;
-bool vis[maxn][maxn][4];
-const ll dir[4][2]={
-    {1,0},
-    {-1,0},
-    {0,1},
-    {0,-1}
+int a[maxn][maxn];
+bool vis[maxn][maxn][4][2];
+int dir[4][2] = {{1, 0}, {0, 1}, {-1, 0}, {0, -1}};
+struct Q {
+    Q(ll s, ll x, ll y, ll dir, bool is2) : s(s), x(x), y(y), dir(dir), is2(is2) {
+    }
+    ll s, x, y, dir;
+    bool is2;
 };
+std::deque<Q> q;
+
+sl bool check(ll x, ll y, ll dir, bool is2) {
+    if (x < 1 || x > n || y < 1 || y > m)
+        return false;
+    if (a[x][y] == 0)
+        return false;
+    if (a[x][y] == 3 && !is2)
+        return false;
+
+    if (a[x][y] == 4) {
+        return !vis[x][y][dir][false];
+    } else {
+        return !vis[x][y][0][is2];
+    }
+}
 
 int main() {
     std::iostream::sync_with_stdio(false);
@@ -30,54 +45,65 @@ int main(){
             std::cin >> a[i][j];
         }
     }
-    d.emplace_back(1,1,0,false);
-    while (d.size()) {
-        auto[x,y,dd,is2,ish] = d.front();
-        d.pop_front();
-        if(ish && a[x][y]==4){
-            ll nx = x+dir[dd][0], ny=y+dir[dd][1];
-            if(a[nx][ny]==3){
-                if(vis[nx][ny][is2])continue;
-            }else if(a[nx][ny]==4){
-                if(vis[nx][ny][dd])continue;
-            }else if(vis[nx][ny][0])continue;
 
-            if(ll na=a[nx][ny];na==0){
-                continue;
-            }else if(na==1){
-                d.emplace_back(nx,ny,dd,false,false);
-                vis[nx][ny][0]=true;
-            }else if(na==2){
-                d.emplace_back(nx,ny,dd,true,false);
-                vis[nx][ny][0]=true;
-            }else if(na==3){
-                continue;
-            }else if(na==4){
-                d.emplace_back(nx,ny,dd,false,true);
-                vis[nx][ny][dd]=true;
+    q.emplace_back(0, 1, 1, 0, false);
+    vis[1][1][0][false] = true;
+
+    while (q.size()) {
+        auto [s, x, y, dd, is2] = q.front();
+        q.pop_front();
+
+        if (x == n && y == m) {
+            std::cout << s << "\n";
+            return 0;
         }
+
+        if (a[x][y] == 4) {
+            ll nx = x + dir[dd][0], ny = y + dir[dd][1];
+
+            if (nx < 1 || nx > n || ny < 1 || ny > m)
+                continue;
+
+            bool nis2 = (a[nx][ny] == 2);
+
+            if (!check(nx, ny, dd, nis2))
+                continue;
+
+            if (a[nx][ny] == 4) {
+
+                vis[nx][ny][dd][false] = true;
+            } else {
+
+                vis[nx][ny][0][nis2] = true;
+            }
+
+            q.emplace_back(s + 1, nx, ny, dd, nis2);
             continue;
         }
+
         for (ll i = 0; i < 4; i++) {
             ll nx = x + dir[i][0], ny = y + dir[i][1];
 
-            if(ll na = a[nx][ny];na==0){
+            if (nx < 1 || nx > n || ny < 1 || ny > m)
                 continue;
-            }else if(na==1){
-                d.emplace_back(nx,ny,i,false,false);
-                vis[nx][ny][0]=true;
-            }else if(na==2){
-                d.emplace_back(nx,ny,i,true,false);
-                vis[nx][ny][0]=true;
-            }else if(na==3){
-                if(is2){
-                    d.emplace_back(nx,ny,i,true,false);
-                    vis[nx][ny][is2]=true;
-                }
-            }else if(na==4){
-                d.emplace_back(nx,ny,i,false,true);
-                vis[nx][ny][i]=true;
+
+            bool nis2 = is2;
+            if (a[nx][ny] == 2)
+                nis2 = true;
+            if (a[nx][ny] == 4)
+                nis2 = false;
+
+            if (!check(nx, ny, i, nis2))
+                continue;
+
+            if (a[nx][ny] == 4) {
+                vis[nx][ny][i][false] = true;
+            } else {
+                vis[nx][ny][0][nis2] = true;
             }
+
+            q.emplace_back(s + 1, nx, ny, i, nis2);
         }
     }
+    std::cout << "-1\n";
 }

src/10/14/P6003cal.cpp

@@ -6,15 +6,15 @@ using ll = int64_t;
 
 
 int main(){
-    ll n,k,m;
-    std::cin>>n>>k>>m;
+    ll n=100,k=100,m=1;
+    // std::cin>>n>>k>>m;
     for(ll x=25;x<=25;x++){
         ll g=0;
         for(ll i=1;i<=k;i++){
             ll y=(n-g)/x;
             y=std::max(y,m);
+            printf("(n-g)=%lld, y=%lld, x=%lld\n",n-g,y,x);
             g+=y;
-            printf("i=%lld, g=%lld\n",i,g);
         }
         printf("-- x=%lld, g=%lld\n\n",x,g);
     }

src/10/16/P6003.cpp

@@ -0,0 +1,44 @@
+#include <algorithm>
+#include <cstdint>
+#include <cstdio>
+#include <iostream>
+#include <istream>
+using ll = int64_t;
+#define sl static inline
+ll n,k,m;
+
+sl bool check(ll x){
+    ll g=0;
+    for(ll i=1;i<=k;i++){
+        ll y=(n-g)/x;
+        if(y<m){
+            g+=m*(k-i+1);
+            return g>=n;
+        }else{
+            ll nxt = ((n-g)-(y*x))/y+1;
+            nxt=std::min(nxt,k-i+1);
+            g+=y*nxt;
+            i+=nxt-1;
+        }
+    }
+    return g>=n;
+}
+
+int main(){
+    std::iostream::sync_with_stdio(false);
+    std::cin.tie(nullptr);
+
+    std::cin>>n>>k>>m;
+    ll l=1,r=n,ans=0,mid;
+    while(l<r){
+        mid=(l+r)/2;
+        // printf("l=%lld, mid=%lld, r=%lld\n",l,mid,r);
+        if(check(mid)){
+            ans=mid;
+            l=mid+1;
+        }else{
+            r=mid;
+        }
+    }
+    std::cout<<ans<<"\n";
+}